Thomas Lee Abshier, ND
—-
Author, Speaker
Naturopathic Physician
Christian Counselor
—
Medical Consultations
Marriage Counseling
Seminars, Speaking
Books, Articles
Audio, Video
—
(503) 255-9500
drthomas@naturedox.com
Portland, Oregon
Photons, Electrons, & Orbitals
By: Thomas Lee Abshier, ND
- ??? Possibly the electron orbital is configured as a wave, along a longitude of the
atom, and the orbital electron only goes up to the next higher electron orbital level
if the electron’s angle with the wave is sufficiently normal (perpendicular) that
the force applied by the photon would be adequate to move the electron up an orbital.
- ??? Possibly when the electron moves up a level, the orbital electron releases a
back EMF that dissipates a portion of the incoming photon, thus allowing it to continue
on, but at a lower level.
- ??? The EM field radiated out by the orbital electron is not confined to the orbital,
it extends out at the speed of light, and will have the same size and extent as the
photon that is coming in to impact on it. Thus, the photon and orbital fields will
add constructively if they are properly phased/aligned. Thus, they will be in the
space where the higher resonant orbital is, and can polarize the space for that electron
to take a piece of that photon for its own kinetic/wave energy.
- ??? Thus, a photon would impact the orbital electron and polarize the electron by
the photon’s E field. But since the Photon also has a B field associated with it,
and the B field is slowed down from light-speed to orbital velocity by finding itself
in the ì and å of the electron mass, the momentum of the photon is thus applied to
the entire electron’s charge-gradient (- in and + out) split-charge structure. Thus,
the new velocity of the electron will be at a tangent to the orbit-point where it
was impacted.
- As a result of the electron having a higher velocity than the velocity at the Bohr
radii, the electron will then begin its exit from the atomic orbital system. If
it has more energy than the highest orbital energy, then it will escape. If not,
then this newly empowered electron will drop the absorbed increment of photonic energy,
re-radiating it out, and dropping back into the resonant orbital.
- The question is thus, why will the electron occupy only the allowable electron orbitals
that are related to integer multiples of Planck’s Constant?
- The energy of the electron as it occupies the orbital is clearly in the form of a
wave as per the fact that the energy of the electron in allowable orbits can be well
calculated by the relationship: E = hí. Likewise, the wavelength of the electrons
in these allowed orbitals is an integral multiple of the bohr radius of simple atoms.
- Thus, it appears that the electron’s constituent DPs are spread out over the diameter
of the orbital as it orbits around the nucleus.
- If in fact the electron’s substance has become spread out over a distance that is
resonant with the diameter of its orbit, this implies that in some way the “head
of the electron has in some way caught up with and merged with its tail.
- In this case, the electron could be considered to have become a standing wave, a
volume containing a sinusoidal organization of Negative DPs and Positive DPs, having
been distributed around the orbital by the dynamically generated E fields and B fields
associated with the dE/dt and dB/dt generated by the movement of the charges in the
space. The standing wave has the appearance of not really moving at all, but underlying
this static appearance is the energetic functionality of movement of particles and
waves, which hold and transmit the momentum associated with the orbital velocity
of a mass.
- The distributed nature of the electron as predicted by the Heisenberg Uncertainty
Principle, and such a wavelike distribution of the electron over the orbital diameter
is obviously consistent with the probabilistic location and difficulty in distinguishing
both its velocity and location; the impact of a probing electron would cause the
condensation of the wave to a greater or lesser extent into a particle with definable
characteristics of velocity and location depending on the velocity of the incoming
electron probe.
- Planck’s constant is in units of angular momentum, and as such it will merely be
a multiplier which relates the energy of the electron/wave to the circumference of
the electron’s orbital.
- The magnetic alignment of the electron and the magnetic fields generated by the momentum
of the electron will interact with the nuclear magnetic field. At the velocity where
the electron wavelength is resonant and creates a standing wave, the pull toward
the nucleus will equal the outer pull of the centrifugal tendency of the electron
to tangentially escape the orbital.
- There are two electrons, with opposite magnetic polarity in the orbital. And since
the electron is in a standing wave structure, with its dynamic magnetic and electrical
forces driving that electron in its orbital velocity, we may assume that the magnetic
effect which we see is related to the direction of the velocity of the orbit.
- As such, the velocity of the second orbital, if it were superimposed upon the first
orbital, and were in an anti-parallel orbit, it would cancel out the magnetic field
produced by the orbital velocity of the first orbital electron in the shell.
- As a result, the magnetic field associated with the velocity of the full shell would
be zero (due to the exactly opposing magnetic fields produced by the antiparallel
orbits). Thus, a magnetically neutral result would be produced by a full orbital
shell.
- The orientation of the DPs (both positive and negative) comprising the mass of the
orbital electron (as they are distributed around the orbital in a sinusoidal concentration-distribution),
they will be entrained to align with the orientation of the magnetic field associated
with the plane they are orbiting in.
