The Heavens Declare His Handiwork

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Thomas Lee Abshier, ND
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(503) 255-9500
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Analogies & Illustrations of:
Photon Wave Packet Phenomenon
By: Thomas Lee Abshier, ND

• Some of the physical characteristics of the photon are as follows:

o The photon has a point of origin, travels at the speed of light through space, and converts its angular momentum into electron orbital velocity when captured.

§ The radio wave is generated by linear movement, transfers its linear momentum to the DP Sea, and converts that EM field into the linear momentum of a current in a receiving antenna.

o The photon’s EM field has a component of forward propagation, and an E field and B field perpendicular to the direction of motion, and perpendicular to each other.  

§ A rotating mass, such as a baseball thrown with a spin, can illustrate some of the properties of the rotating EM field.

§ A dot placed on the baseball will trace out a sinusoidal path as it travels, just as the point of maximum E or B field intensity will trace out a sinusoidal path as it travels.

o The photon’s E field varies in a plane perpendicular to the centerline path of the photon’s forward motion.  Likewise, the B field varies in a plane perpendicular to the forward motion of the photon, and perpendicular to the B field.  When the E field is horizontal and parallel to the horizon that photon is polarized horizontally.  Likewise, when the photon’s E field is oriented vertically/perpendicular to the horizon, it is vertically polarized.  The angle of the E field’s vector with reference to the horizon defines the photon’s angle of polarization.  

o The excursion of the field around the centerline of propagation is equal to the wavelength of the photon.

§ The amplitude of the photon can be understood as the distance the E field travels away from centerline, and it will have an amplitude, or distance of excursion, equal to ½ wavelength.  This will be true regardless of the wavelength of the photon (i.e. its color, frequency, or energy) because the lateral component of the EM field will travel at the speed of light at the same time the forward component is traveling at the speed of light.  Thus, the forward wavelength will equal the lateral excursion distance-amplitude.

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